Saturday, 2 June 2012

From integrating multiplier to integrating operator

I thought about this trick first and then found an example to apply it to.
$$\ln|1+x+y|=(y-x)+\ln C$$
I am still not sure if this is a one-off case or if it can be generalised to a consistent method. It all spins around the understanding of \(d\) as a linear operator when it comes up in equations and integrals. This is something I discuss at greater length in my self-published book

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